Generate PHP models from JSON and inspect the conversion helpers
JSON to PHP creates starter model code from a JSON example. It helps translate observed data fields into a more explicit PHP representation.
When should you use it?
- Prototype classes around an API response.
- Document expected fields in a PHP integration.
- Compare nested fixture data with existing models.
Example: infer PHP fields from JSON
This abbreviated example shows the inferred name and active fields in PHP. The full generated file includes imports and helpers and may change with generator versions; review it before adding it to a project.
{"name":"Alex","active":true}class Root {
private string $name;
private bool $active;
}Use models to make nested data easier to work with
Generated classes can replace repeated string-key access with a clearer representation of a response. The full output may include accessors and conversion helpers in addition to properties. Review that code as a unit, then decide how it fits your application framework and supported PHP version rather than copying only a short class excerpt.
Check nulls, numeric limits, and field naming
A sample describes observed values, so review optional fields against the actual contract. Large identifiers may need strings rather than numeric conversion, and a nullable value needs a representation that your application handles consistently. Test conversion with nested records, missing properties, and null values in your own environment. The browser generator produces code but does not execute a PHP runtime.
How do I generate PHP model classes from JSON records?
Generate PHP source from a JSON example, then review its property types and conversion methods against your project’s PHP version. The output is a starting model for observed fields rather than a complete runtime contract.
Illustrative PHP fields
phpclass Root {
private string $name;
private bool $active;
}The full .php file includes a constructor and mapping helpers. Adjust optionality and unexpected-field handling for your API.
Can a single JSON sample reveal every nullable PHP property?
No. Absent properties and null variants need examples or an API schema. Verify those cases before relying on generated type declarations.
What should you check before using the result?
Review property types, names, null handling, parsing approach, and target PHP version before use. This generation is a starting draft, not a runtime schema check.
Understand JSON syntaxTechnical reference: quicktype model generation documentation